#Numbers-15
In a division sum, the remainder was 71. With the same divisor but twice the dividend, the remainder is 43. Which one of the following is the divisor?
(i)86
(ii)93
(iii)99
(iv)104
Solution-
We know that,
Dividend = Quotient*Divisor + Remainder
Let the Dividend = D
Quotient = Q
Divisor = d
=> D = d*Q + 71----------(i)
Also,
2D = d*q + 43-------(ii)
Subtracting eqn 2*(i) from (ii),
0 = d*(q - 2Q) - 99
=> d*(q - 2Q) = 99
Now, 99 = 1*99 or 3*33 or 9*11
d*(q - 2Q) = 1*99 or 3*33 or 9*11
Checking options we can see only one value of d satisfies,
Hence, d = 99 ANS
(i)86
(ii)93
(iii)99
(iv)104
Solution-
We know that,
Dividend = Quotient*Divisor + Remainder
Let the Dividend = D
Quotient = Q
Divisor = d
=> D = d*Q + 71----------(i)
Also,
2D = d*q + 43-------(ii)
Subtracting eqn 2*(i) from (ii),
0 = d*(q - 2Q) - 99
=> d*(q - 2Q) = 99
Now, 99 = 1*99 or 3*33 or 9*11
d*(q - 2Q) = 1*99 or 3*33 or 9*11
Checking options we can see only one value of d satisfies,
Hence, d = 99 ANS
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