#Algebra-3

If  x^2 - x - 1 = 0 , then find the value of (x^8-1)/(x^3+x^5)

a)2
b)3
c)4
d)none









Solution:-


x^2 = x + 1

x^8 - 1 = (x^2)^4 - 1 = (x + 1)^4 - 1 = x^4 + 4x^3 + 6x^2 + 4x + 1 - 1 = x(x^2 + 2x + 2)(x + 2) = x(3x^2)(x^2 + 1)

x^3 + x^5 = x^3(x^2 + 1)

=> (x^8 - 1)/(x^3 + x^5) = x(3x^2)(x^2 + 1)/x^3(x^2 + 1) = 3









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