#Numbers-14

There is a number 49A81B.How many pairs of (a,b) are possible when divided by 66?

a)0  b)1 c)2 d)None of these







Solution:-

B=0,2,4,6,8 ---(1)
22+a+b = 3k ---(2)
B-a+12=11k ---(3)
For (3) to be true, a,b are consecutive numbers where b<a.

So possibilities (a,b)= (2,0)(3,2)(5,4)(7,6)(9,8)

Now putting these values in eq (2) you can check. Two pairs satisfy (3,2) and (9,8)

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