#Numbers-9

When a certain two-digit number is added to another two digit number having the same digits in reverse order, the sum is a perfect square. How many such two-digit numbers are there?


(1) 4 (2) 6 (3) 8  (4) 10



Solution:-

A=10x+y
B=10y+x
-------------
11(x+y)

x+y=11 (to be a perfect square)




4*2=8(answer)








Lets solve another question but a bit on the tougher side.....

Consider four-digit numbers for which the first two digits are equal and the last two digits
are also equal. How many such numbers are perfect squares?

(1) 3 (2) 2 (3) 0 (4) 1

We will give the solution in the next post....

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