#Numbers-11

ABCD is a perfect square.Given that C:D=4:1.Find Max[ABCD]







Solution:-

Search for squares whose last two digits are in the ratio of 4:1

21^2=441

(50(n)+21=21,51)...where n=0,1
(50(n)-21=29,79)...where n=0,1

79^2=6241

Note:-Do memorize Squares upto 25

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