Qu@ntose

  While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the product went up by 720. Then the minimum possible value of the sum of squares of the other two numbers is _________? SOLUTION  -                        Let the other two numbers be x and y.                                              Correct Product = x*y*37                       Incorrect Product = x*y*73                      Difference = 720                 => 73xy - 37xy = 720                 => 36xy = 720                 => xy = 20 -----------------(i)              Now, we know that,                             (x^2 + y^2)/2  ≥  (x^2 * y^2)^(1/2)    [ AM ≥ GM ]                        => (x^2 + y^2)  ≥ 2*(xy)            => (x^2 + y^2) ≥ 2*20                     => (x^2 + y^2) ≥ 40 ANS